Merry students roam the campus
3204. I am the God of Gamblers 7
Carefully observe the above 3 matrices, and many winning strategies can be understood with a little thought. [, but there are also some very interesting points, for example, when the sum of the hand cards is 12, the dealer should hit if the board is 2 or 3, and stand if the board is 4 to 6.
why?When to ask for a card and when not to, the probability has the final say.Let us first take a look at the winning percentage of the stand when the player is at 12 points.After the dealer starts to draw cards, the sum of the points will be greater than or equal to 17.At this time, if the player wants to win, he can only hope that the dealer will blow his cards.
If the dealer's starting point is greater than or equal to 17, there is no need to draw cards at all.When the sum of the points is h16, if you draw 6~t, it will explode.We know that the probability of drawing cards of different sizes is equal (1/13), let f(x) be the probability of continuing to draw cards and blow up when the current point sum is x, then:
f(h16)=8/13=0.61538
When the sum of the banker's hand points is h15, it will explode if it draws 7~t; if it draws a, it will be reduced to h16:
f(h15)=7/13+1/13xf(h16)=0.58580
In the same way, the bust probability from h14 to h6 can be calculated.When the dealer's hand is h5, the situation is different. At this time, a can be counted as 11 points. After taking this change into consideration, it is not difficult to calculate the situation of h2h5.
What if the player chooses to hit?There are two winning situations at this point:
The player does not bust but the dealer busts
Neither the player nor the banker exploded, but the banker's points are small
The probability of busting has been calculated, now let's consider the situation of ratio.If the dealer's first card is a 2, let g(x) be the probability of the dealer getting a hand with a sum of points of x, then g(h2)=1.
If the sum of the banker's hand becomes h3, he can only draw an a in the case of h2, that is:
g(h3)=1/13xg(h2)=0.07692
Similarly, the probability from h4 to h21 can be calculated, and attention should still be paid to the fact that a is counted as 11 points.In the case that both sides do not bust, there are only the following possibilities for the player to win by comparing the size:
The player gets 21 points, the banker gets 20~17 points
The player gets 20 points, the banker gets 19~17 points
The player gets 19 points, the banker gets 18 and 17 points
The player gets 18 points and the banker gets 17 points
The player draws cards from 12 o'clock and gets 18 points, which is equivalent to starting from h2 and getting h8, so the probability is g(h8), and the probability of the dealer getting 17 points is g(17).The probability of case 4 is thus:
p4=g(h8)xg(17)
In the same way, p3, p2, and p1 can be calculated.Therefore, when the player's hand sum is h12 and the dealer's first card is 2, the player's winning probability of choosing hit is:
p(h)=p1+p21+p22+p23+p24=0.36958
Calculated before, in this case, the probability of winning by standing is p(s)=f(h2)=0.35831
p(h)>p(s), so hit is the optimal strategy.
Using the same method, we can calculate the probability that the player chooses hit to win when the player's hand is h12 and the dealer's first card is h3~h11.
It is said that only those with an IQ of 160 can understand these biography.As for those "scumbags with an intelligence of 5", don't even think about it!
Well, lucky!Chen Ming's children's shoes have at least reached the standard of [-]. He can fully understand and use this set of diagrams.Therefore, the tens of thousands of chips increased rapidly, reaching hundreds of thousands in a short time.
Then, I went to play hoe big d with others. This game is completely throwing money, luck, and brains.Previously, we played from a table of seven or eight people to a table of three people.Not long after, the chips in front of him exceeded 300 million!
,-,
why?When to ask for a card and when not to, the probability has the final say.Let us first take a look at the winning percentage of the stand when the player is at 12 points.After the dealer starts to draw cards, the sum of the points will be greater than or equal to 17.At this time, if the player wants to win, he can only hope that the dealer will blow his cards.
If the dealer's starting point is greater than or equal to 17, there is no need to draw cards at all.When the sum of the points is h16, if you draw 6~t, it will explode.We know that the probability of drawing cards of different sizes is equal (1/13), let f(x) be the probability of continuing to draw cards and blow up when the current point sum is x, then:
f(h16)=8/13=0.61538
When the sum of the banker's hand points is h15, it will explode if it draws 7~t; if it draws a, it will be reduced to h16:
f(h15)=7/13+1/13xf(h16)=0.58580
In the same way, the bust probability from h14 to h6 can be calculated.When the dealer's hand is h5, the situation is different. At this time, a can be counted as 11 points. After taking this change into consideration, it is not difficult to calculate the situation of h2h5.
What if the player chooses to hit?There are two winning situations at this point:
The player does not bust but the dealer busts
Neither the player nor the banker exploded, but the banker's points are small
The probability of busting has been calculated, now let's consider the situation of ratio.If the dealer's first card is a 2, let g(x) be the probability of the dealer getting a hand with a sum of points of x, then g(h2)=1.
If the sum of the banker's hand becomes h3, he can only draw an a in the case of h2, that is:
g(h3)=1/13xg(h2)=0.07692
Similarly, the probability from h4 to h21 can be calculated, and attention should still be paid to the fact that a is counted as 11 points.In the case that both sides do not bust, there are only the following possibilities for the player to win by comparing the size:
The player gets 21 points, the banker gets 20~17 points
The player gets 20 points, the banker gets 19~17 points
The player gets 19 points, the banker gets 18 and 17 points
The player gets 18 points and the banker gets 17 points
The player draws cards from 12 o'clock and gets 18 points, which is equivalent to starting from h2 and getting h8, so the probability is g(h8), and the probability of the dealer getting 17 points is g(17).The probability of case 4 is thus:
p4=g(h8)xg(17)
In the same way, p3, p2, and p1 can be calculated.Therefore, when the player's hand sum is h12 and the dealer's first card is 2, the player's winning probability of choosing hit is:
p(h)=p1+p21+p22+p23+p24=0.36958
Calculated before, in this case, the probability of winning by standing is p(s)=f(h2)=0.35831
p(h)>p(s), so hit is the optimal strategy.
Using the same method, we can calculate the probability that the player chooses hit to win when the player's hand is h12 and the dealer's first card is h3~h11.
It is said that only those with an IQ of 160 can understand these biography.As for those "scumbags with an intelligence of 5", don't even think about it!
Well, lucky!Chen Ming's children's shoes have at least reached the standard of [-]. He can fully understand and use this set of diagrams.Therefore, the tens of thousands of chips increased rapidly, reaching hundreds of thousands in a short time.
Then, I went to play hoe big d with others. This game is completely throwing money, luck, and brains.Previously, we played from a table of seven or eight people to a table of three people.Not long after, the chips in front of him exceeded 300 million!
,-,
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