Required Mathematical Intelligence
Chapter 77 Ace
Chapter 77 Ace
In a game of poker, someone has a deck of cards like this:
(1) There are exactly thirteen cards.
(2) At least one card of each suit.
(3) The number of sheets of each suit is different.
(4) There are five hearts and squares in total.
(5) There are six hearts and spades in total.
(6) There are two cards belonging to the suit of the "trump card".Among the four suits of hearts, spades, diamonds and clubs, which one is the "trump" suit?
[Answer: According to (1), (2), and (3), the distribution of the four suits in this person's hand is one of the following three possible situations:
(a) 1237
(b) 1246
(c) 1345
According to (6), case (c) is ruled out because none of the suits in it are two cards.According to (5), case (a) is ruled out because the sum of cards of any two suits in it is not six.
Therefore, (b) is the actual suit distribution.According to (5), there are either two hearts and four spades, or four hearts and two spades.
According to (4), there are either one heart and four diamonds, or four hearts and one diamond.Combining (4) and (5), there must be four hearts; thus there must be two spades.Therefore, spades are the trump suit.
To sum up, this person has four hearts, two spades, one diamond and six clubs in his hand. ]
(End of this chapter)
In a game of poker, someone has a deck of cards like this:
(1) There are exactly thirteen cards.
(2) At least one card of each suit.
(3) The number of sheets of each suit is different.
(4) There are five hearts and squares in total.
(5) There are six hearts and spades in total.
(6) There are two cards belonging to the suit of the "trump card".Among the four suits of hearts, spades, diamonds and clubs, which one is the "trump" suit?
[Answer: According to (1), (2), and (3), the distribution of the four suits in this person's hand is one of the following three possible situations:
(a) 1237
(b) 1246
(c) 1345
According to (6), case (c) is ruled out because none of the suits in it are two cards.According to (5), case (a) is ruled out because the sum of cards of any two suits in it is not six.
Therefore, (b) is the actual suit distribution.According to (5), there are either two hearts and four spades, or four hearts and two spades.
According to (4), there are either one heart and four diamonds, or four hearts and one diamond.Combining (4) and (5), there must be four hearts; thus there must be two spades.Therefore, spades are the trump suit.
To sum up, this person has four hearts, two spades, one diamond and six clubs in his hand. ]
(End of this chapter)
You'll Also Like
-
The original god's plan to defeat the gods is revealed, starting with the God of Fire saving th
Chapter 117 1 hours ago -
The end of the world: My refuge becomes a land of women
Chapter 430 1 hours ago -
Return to Immortality: One point investment, a billion times critical hit!
Chapter 120 1 hours ago -
Steel, Guns, and the Industrial Party that Traveled to Another World
Chapter 764 1 days ago -
The Journey Against Time, I am the King of Scrolls in a Hundred Times Space
Chapter 141 1 days ago -
Start by getting the cornucopia
Chapter 112 1 days ago -
Fantasy: One hundred billion clones are on AFK, I am invincible
Chapter 385 1 days ago -
American comics: I can extract animation abilities
Chapter 162 1 days ago -
Swallowed Star: Wish Fulfillment System.
Chapter 925 1 days ago -
Cultivation begins with separation
Chapter 274 1 days ago