I Just Want to Be a Quiet Top Student

Shen Qi wrote his point on the blackboard:

Res(g(s)-2k)=Τ(s)ζ(s)(2α)^-s……

"When k is greater than or equal to 1, s=0 is the first-order pole of g(s). I transform τ into -2k-s in the integral of this formula..." Shen Qi said loudly, knocking one on the blackboard Formula: "Then get this formula, then the sum number path transformation can be transformed into the sum number in the twin matching method. Based on this setting, the first expression of ζ(s) I obtained is valid. That is Say, I did not use any theory in Hardy's system, Hardy's system is a classic system, but the 21st century needs a new and more advanced system, thank you."

Shen Qi's generous statement was justified and well-founded, and won the approval of most of the experts present.

"There is a contradiction between Euclidean geometry and Lobachevsky geometry, but both systems are being used. There is no absolute right or wrong." Kabrowski said in the first question. Last he supported Shen Qi.

"We have studied Newton's classical mechanics system, and we have also studied the quantum mechanics system. Newton is not wrong, Einstein and Schrödinger are equally correct." Rodriguez added.

"Shen is an excellent scholar, but no one can compare with Einstein, Schrodinger, and Lobachevsky." Maynard was a little excited.

"Don't be so excited, Professor Maynard, I think what Professor Kabrovsky and Professor Rodriguez said is reasonable. Shen's twin matching method is not contrary to Hardy's system. Day and night will not exist at the same time. But they all have meaning." The neutral Canadian mathematician Carrick gradually leans towards Shen Qi. He believes that Shen Qi's answer to the first question is reasonable and there are no loopholes in logic, and Shen Qi's new theory is valid.

"Professor Kabrowski, Professor Rodriguez, and Professor Carrick. We have been discussing the first question for two months in Sweden. I still support Professor Maynard’s point of view. Only the Hardy system is The only correct way to solve Riemann's conjecture." Australian mathematician Wilson stepped forward, and he stood on Maynard's side with a clear attitude.

"Hardy and Ramanujan failed to prove Riemann's conjecture. What is missing is time, and we have plenty of time. We should follow the correct path of Hardy and Ramanujan." Saba, a curly-haired Indian mathematician Xin, he really was with Maynard. Maynard supported the British master Hardy. Sabahsin did not forget to move out of Ramanujan, Hardy's best partner, the pride of Indians.

Shen Qi watched the three mathematicians from the Commonwealth countries coldly. It's normal. This is normal. Even if what I say is reasonable, someone will always come out and accuse me.

At this time, Kenji Nakamura, a mathematician from the University of Tokyo in Japan, stood up. He walked to the blackboard, picked up the chalk and wrote:

ρ1, 1-ρ1

ρ2, 1-ρ2

ρ3, 1-ρ3

...

ρn, 1-ρn

...

ζ(s)=e^A+Bs∏∞n=1(1-s/ρn)(1-s/1-ρn)e^(s/ρn+s/1-ρn)

After writing, Kenji Nakamura said: "I have studied Shen's twin matching method in depth. I used the vertical combination method to derive the exact same conclusion as Shen's first expression. We should respect the facts and respect. As for the laws of mathematics, Shen's theory is correct. This is undoubtedly the most basic mathematical law."

Shen Qi was very surprised, oh, Nakamura, a Niben person, actually supported me. He used the basic theorem of algebra to verify my twin matching method and the first expression. It was quite thoughtful, wonderful!

There is justice in the world, and mathematicians with real conscience and professionalism are concerned about mathematics itself, and all other factors are not within the scope of the review.

Starting from the basic theorem of algebra, Kenji Nakamura verified that Shen Qi's new theory is logically valid.

"I still stick to my point of view, and I also obey the rules of the jury. In the final decision-making process, let's vote." Maynard is particularly stubborn, like most British people.

The current situation is: Support 4: Opposition 3: Neutral 4.

Shen Qixin said that in your voting session, you recognized my proof of Riemann's conjecture. Do you need more than 50% or more than 80% of the votes?

Isn't it a one-vote veto system?

The voting settings must be clear, otherwise Maynard will be determined to target me to death, then I will get a woolen thread.

"6 votes, 11 of us voted more than 6 votes, including 6 votes, then IMU and "Acta Mathematica" will recognize your paper." The head of the jury Kabrowski explained to Shen Qi I've reviewed the voting rules.

"It's fair, isn't it." Shen Qi felt confident and asked, "So we don't have to worry about the Hardy system anymore, right?"

"Go to the next question. This question is a question I have always cared about." This time it was Kabrowski's turn to ask questions. He asked Shen Qi, how to explain that under the setting of the twin matching method, ρ must be the first-order zero point?

This question is well asked, professional and standard, high-end is very high-end.

Kabrowski’s questions were objective and fair. Starting from the mathematics itself, Shen Qi believed that it was necessary to explain clearly to the jury.

Shen Qi answered with a lot of energy, and it was 12 noon after answering the second question.

For four hours in the morning, Shen Qi answered two questions in total.

The review experts are very professional, they pay attention to any suspicious details, and they can't be done in 45 minutes.

If the "Proof of Riemann Conjecture Based on the "Twin Matching Method" is to pass the review, it means that more than six experts have no doubts in every detail, that is to say, Shen Qi must get more than six full marks. .

One afternoon passed, and two new questions were answered perfectly by Shen Qi.

After the night battle, the jury asked a total of 8 questions today, exhausting Shen Qi into a dog.

Fortunately, the result was quite satisfactory. Shen Qi's instinct told him that the number of supporters had reached about six.

It was dawn, and the review continued. On the second review day, Shen Qi answered 5 questions.

After three consecutive days of trial, Shen Qi carried it over, but the old Kabrowski head was exhausted.

On the fourth day, the head of Kabrowski came to work with illness. He asked the last question of this review: "If Riemann’s conjecture is true, then Shen, how do you explain logζ(σ+it)<<(log ∣t∣)^2-2σ+ε, where ∣t∣≥2, ε＞0, 1/2≤σ≤1."

According to Shen Qi's observation, the current situation is support 6: Opposition 3: Neutral 2.

After answering the last question, the overall situation is set!

This question is a new question derived from the main text of the thesis. Shen Qi took a chalk and wrote on the blackboard. After writing a set of formulas, he knocked on the blackboard with a passionate tone: "I proved that I am in circle∣s-s0 ∣≤3/2-σ has logζ<<σ^-1log∣t∣, ∣t∣≥2. Obviously, the <

Shen Qi broke out, the thunderbolt!

Maynard was startled and accidentally spilled coffee on his trousers.

Except for the three Commonwealth mathematicians, Maynard, Wilson, and Sabassin, sitting on the chair, the other eight mathematicians stood up~www.readwn.com~ with excitement.

"Shen, you actually came up with this kind of proof method temporarily in such a short time!"

"Perfect proof, Riemann's conjecture is the correct proposition!"

"Let's vote, yes, there is nothing to ask, Shen is a genius, let us vote for geniuses!"

Boom!

Shen Qi tapped on the blackboard: "Please sit down first, I haven't finished."

The situation was very good, and the eight mathematicians in the jury were completely conquered by Shen Qi.

There are now 8 affirmative votes!

Shen Qi has almost become a god, and all that is left is a matter of time.

Appreciating, applauding, frustrated, helpless, or dissatisfied, a variety of emotions are mixed in the conference room.

Under the attention of everyone, Shen Qi suddenly inspired to write a new formula. He knocked on the blackboard with excitement: "If Riemann's conjecture is established, there is another situation when 1/2+(loglog∣t∣) When ^-1≤σ≤1, there is logζ(s)<<(loglog∣t∣)(log∣t∣)^2-2σ, where <

brush!

The Indian mathematician Sabbasin couldn't help jumping up, his staring boss, his curly hair was straightened: "Yes, he is right, genius-like imagination, devil-like deduction logic..."

Seeing the evil appearance of Sabah Sin, Maynard is so angry that the Indian is too unreliable. This is the **** Shen Qi instigated?

Maynard looked at the blackboard. As a top number theory expert, he had to admit that Shen Qi did possess a genius brain and devilish logic...

...

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